4.3.1 Overriding Methods

Overriding fields is instrumental for creating class hierarchies. Many design patterns utilize it, but here we will explore only the basic functionality. In order to use overrides in a class, it is required that this class has a parent class. Let us consider the following example:

class Base {
  public function new() {}

  public function myMethod() {
    return "Base";
  }
}

class Child extends Base {
  public override function myMethod() {
    return "Child";
  }
}

class Main {
  static public function main() {
    var child:Base = new Child();
    trace(child.myMethod()); // Child
  }
}

The important components here are:

• the class Base which has a method myMethod and a constructor,
• the class Child which extends Base and also has a method myMethod being declared with override, and
• the Main class whose main method creates an instance of Child, assigns it to a variable child of explicit type Base and calls myMethod() on it.

The variable child is explicitly typed as Base to highlight an important difference: At compile-time the type is known to be Base, but the runtime still finds the correct method myMethod on class Child. This is because field access is resolved dynamically at runtime.

The Child class can access methods it has overridden by calling super.methodName():

class Base {
  public function new() {}

  public function myMethod() {
    return "Base";
  }
}

class Child extends Base {
  public override function myMethod() {
    return "Child";
  }

  public function callHome() {
    return super.myMethod();
  }
}

class Main {
  static public function main() {
    var child = new Child();
    trace(child.callHome()); // Base
  }
}

The section on Inheritance explains the use of super() from within a new constructor.

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